The coach of a cricket team buys 7 bats and 6 balls for 3800 rupees. Later, she buys another 3 bats and 5 balls for 1740 rupees. find the cost of each bat and ball.
solve either using substitution or elimination method
Answers
Answer:
Bat = 500, Ball = 50
Explanation:
Set up the two individual equations, then combine them to solve for each item.
1) 7bat + 6ball = 3800
2) 3bat + 5ball = 1750
Multiply the second equation by 7 and the first one by 3, then subtract the first equation from the second to obtain an equation for the balls. Solve that equation and then substitute the value for balls into either equation to solve for bats. Use the other equation to check your final values.
1) (7bat + 6ball = 3800) * 3
2) (3bat + 5ball = 1750) * 7
1) 21bat + 18ball = 11400
2) 21bat + 35ball = 12250
2) - 1):
17*ball = 850 ; ball cost = 50
1) 7bat + 6ball = 3800 ; 7bat + 6(50) = 3800
7*bat = 3500 ; bat cost = 500
CHECK!
2) 3bat + 5ball = 1750 ; 3(500) + 5(50) = 1750 ; 1500 + 250 = 1750 ; 1750 = 1750 CORRECT!