The coach of a cricket team buys 7 bats and 6 balls for 13200. Later he buys 3 bats and 5 balls for 5900. find the cost of each bat and each ball.
Answers
Explanation:
Given:
- Cost of 7 bats and 6 balls is Rs 13200.
- Cost of 3 bats and 5 balls is Rs 5900.
To Find:
What is the cost of each bat and ball ?
Solution:
- Let the cost of each bat and ball be Rs x and y respectively.
➙ Cost of 7 bats = Rs 7x
➙ Cost of 6 balls = Rs 6y
Equation 1
➙ Cost of 3 bats = Rs 3x
➙ Cost of 5 balls = Rs 5y
Equation 2
[ Multiplying 5 in equation 1 and 6 in equation 2 ]
➯ (7x + 6y) 5 = 13200 × 5
35x + 30y = 66000ㅤㅤㅤeqⁿ i
➯ (3x + 5y) 6 = 5900 × 6
18x + 30y = 35400ㅤㅤeqⁿ ii
ㅤㅤㅤㅤㅤ35x + 30y = 66000
ㅤㅤㅤㅤㅤ18x + 30y = 35400
ㅤㅤㅤㅤㅤ–ㅤㅤ–ㅤㅤ–
ㅤㅤㅤㅤ━━━━━━━━━━━━━━━
Now putting the value of x in equation 1.
Hence, the cost of each bat and ball is Rs 1800 & Rs 100 respectively.
_____________________
Explanation:
Given :-
The coach of a cricket team buys 7 bats and 6 balls for 13200. Later he buys 3 bats and 5 balls for 5900
To Find :-
Cost of one bat and ball
Solution :-
Let
Price of bat = x
Price of ball = y
Now
7 × x + 6 × y = 13200
7x + 6y = 13200
Multiply by 5
5(7x + 6y) = 5(13200)
35x + 30y = 66000(1)
Now
3 × x + 5 × y = 5900
3x + 5y = 5900
Multiply by 6
6(3x + 5y) = 6(5900)
18x + 30y = 35400
Subtracting them
(35x + 30y) - (18x + 30y) = 66000 - 35400
35x + 30y - 18x - 30y = 30600
35x - 18x = 30600
17x = 30600
x = 30600/17
x = 1800
By putting in 1
35(1800) + 30y = 66000
63000 + 30y = 66000
30y = 66000 - 63000
30y = 3000
y = 3000/30
y = 100