Math, asked by legendkushal, 1 year ago

the coach of a cricket team buys 7 bats and 6 balls for rupees 3800 later she buys 3 beds and 5 Balls for Rs 1750 find the cost of each bat and ball

Answers

Answered by devansh2601
0
Let the cost of bat be Rs.x and of ball be Rs.y.

According to given,

7x+6y=3800

and

3x+5y= 1750

Now, solve it simultaneously to get x and y.
Answered by Battleangel
8

let the cost of 1 bat be₹X

cost of 1 ball =Y

7x+6y=3800----------(i)

3x+5y=1750-----------(ii)

from (i) 7x+6y=3800

 \:  \:  \:  \:  \:  \:  \:  7x = 3800 - 6y

x =  \frac{3800 - 6y}{7}

substituting \: x =  \frac{3800 - 6y}{7} \: in \: equation(ii)

 \implies \: 3( \frac{3800 - 6y}{7} ) + 5y = 1750

 \implies \:  \frac{11400 - 18y}{7}  + 5y = 1750

 \implies \:  \frac{11400 - 18y}{7}  + 35y =  1750

 \implies \:  \frac{11400 + 17y}{7}  = 1750

\implies \:  11400 + 17y = 1750 \times 7

\implies \:  11400 + 17y = 12250 \\ \implies \:  17y = 12250 - 11400

\implies \: 17y= 850

 \implies \: y =  \frac{850}{17}

 \implies \: y = 50

putting \: y \:  = 50 \: in \: equation \: (iii)

x =  \frac{3800 - 6(50)}{7}

 \implies \: x =  \frac{3800 - 300}{7}

 \implies \: x =  \frac{3500}{7}

 \implies \:  x\:  = 500

 \therefore \: cost \: of \: 1 \: bat = 500 \\ cost \: of \: 1 \: ball \:  = 50

Hey Mark as brainliest xD

Similar questions