the coach of a cricket team buys 7 bats and 6 balls for Rs.3800.Later ,she buys 3 bats and 5 balls for Rd.1750. Find the cost of each bat and each ball .
solve by substitution method
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Answers
solution:
let the cost of the each bat be=Rs x
let the cost of the each ball be=Rs y
=> 7x + 6y =3800
=>6y =3800 - 7x
Dividing by 6,we get
=> y =(3800-7x)/6
(1) 3x+5y=1750
putting the value of y
=>3x+5[(3800-7x)/6] = 1750
multiplying by 6,we get
=>18 x 19000 - 35x = 10500
=> -17x = 10500 - 19000
=> -17x = - 8500
=> x = - 8500/-17
=> x = 500
putting this value in equation (1) we get
=> y = (3800 -7 × 500)/6
=> y =300/6
=> y = 50
Hence, the cost of each bat is =Rs 500 and the cost of each ball is = Rs 50
Given :
- The coach of a cricket team buys 7 bats and 6 balls for Rs.3800.
- Also, she buys 3 bats and 5 balls for Rs.1750.
To Find :
- Cost of each bat and each ball.
Solution :
Let the cost of bat be ₹ x.
Let the cost of ball be ₹ y.
Case 1 :
Cost of 7 bats and 6 balls is 3800.
✪ Equation :
____(1)
Case 2 :
Cost of 3 bats and 5 balls is ₹ 1750.
✪ Equation :
✪ Substite value of x from equation 1,
✪ Substitute y = 50 in equation 1,