The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, she buys 3 bats and 5 balls for Rs 1750. Find the cost of each bat and each ball.
Answers
Answer:
Explanation:
Given :-
The coach of cricket teams buys 7bats and 6 balls for 3800.
Later she buys 3 bats and 5 balls for rs 1750.
To Find :-
Cost of each ball and bat
Solution :-
Let the cost of each bat be = Rs x
Let the cost of each ball be = Rs y
According to the Question,
⇒ 7x + 6y = 3800
⇒ 6y = 3800 - 7x
Dividing by 6, we get
⇒ y = (3800 - 7x)/6 … (i)
⇒ 3x + 5y = 1750
Putting the value of y
⇒ 3x + 5 ((3800 - 7x)/6) = 1750
Multiplying by 6, we get
⇒ 18x + 19000 - 35x = 10500
⇒ -17x =10500 - 19000
⇒ -17x = - 8500
⇒ x = - 8500/-17
⇒ x = 500
Putting this value in equation (i) we get
⇒ y = ( 3800 - 7 × 500)/6
⇒ y = 300/6
⇒ y = 50
Hence the cost of each bat is Rs 500 and the cost of each balls is Rs 50.
Answer:
Let the Cost of 1 bat be a and Cost of 1 ball be b respectively.
☯ According to the Question :
⇾ 7a + 6b = 3800 — eq. ( I ) × 3
⇾ 3a + 5b = 1750 — eq. ( II ) × 7
☢ Subtracting after Multiplying:
⇴ 21a + 18b = 11,400
⇴ 21a + 35b = 12,250
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⇴ 18b – 35b = 11,400 – 12,250
⇴ 17b = 850
- Dividing both term by 17
⇴ b = 50 [ Cost of 1 Ball ]
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☢ Putting value of b in eq. ( I ) :
⇢ 7a + 6b = 3800
⇢ 7a + 6(50) = 3800
⇢ 7a + 300 = 3800
⇢ 7a = 3800 – 300
⇢ 7a = 3500
- Dividing both term by 7
⇢ a = 500 [ Cost of 1 Bat ]
∴ Cost of Each Bat and Each Ball is Rs. 500 & Rs. 50 respectively.