The coach of a cricket team buys 7 bats and 6 balls for Rs.3800. Later, she buys 3 bats and 5 balls for Rs.1750. Find the cost of each bat and each ball.
Answers
Let the cost of a bat be x and the cost of a ball be y.
According to the question,
7x + 6y = 3800 ………………. (i)
3x + 5y = 1750 ………………. (ii)
From (i), we get;
y = (3800 – 7x)/6 …………………… (iii)
Substituting (iii) in (ii). we get,
3x + 5[(3800 – 7x)/6] = 1750
⇒3x + (9500/3) – (35x/6) = 1750
3x – (35x/6) = 1750 – (9500/3)
(18x – 35x)/6 = (5250 – 9500)/3
⇒-17x/6 = -4250/3
⇒-17x = -8500
x = 500
Putting the value of x in (iii), we get;
y = (3800 – 7 × 500)/6 = 300/6 = 50
Hence, the cost of a bat is Rs 500 and cost of a ball is Rs 50.
Given:
➪The cost of cricket teams buys 7 bats and 6 balls for 3800 later she buys 3 bats and 5 balls for₹1750.
To find
➪Cost of each ball and bat
solution
➪let the cost of each bat be=₹ x
➪let the cost of each ball be = ₹ y
According to the Question
➪7x+6y=3800
6y= 3800-7x/6. _________ 1
➪3x+5y=175
putting the value y
3x+5 ((3800-7x))/6 = 1750
x= 500
y= (3800-7x)/6 = (3800-7(500))/6 = 50
y= 50
Hence the cost of each bat= Rs 500 and the each cost of balls = Rs 50✔︎✔︎✔︎✔︎✔︎✔︎✔︎