Math, asked by Anonymous, 6 months ago

The coach of a cricket team buys 7 bats and 6 balls for Rs.3800. Later, she buys 3 bats and 5 balls for Rs.1750. Find the cost of each bat and each ball.​

Answers

Answered by MrDRUG
5

Let the cost of a bat be x and the cost of a ball be y.

According to the question,

7x + 6y = 3800 ………………. (i)

3x + 5y = 1750 ………………. (ii)

From (i), we get;

y = (3800 – 7x)/6 …………………… (iii)

Substituting (iii) in (ii). we get,

3x + 5[(3800 – 7x)/6] = 1750

⇒3x + (9500/3) – (35x/6) = 1750

3x – (35x/6) = 1750 – (9500/3)

(18x – 35x)/6 = (5250 – 9500)/3

⇒-17x/6 = -4250/3

⇒-17x = -8500

x = 500

Putting the value of x in (iii), we get;

y = (3800 – 7 × 500)/6 = 300/6 = 50

Hence, the cost of a bat is Rs 500 and cost of a ball is Rs 50.

Answered by Prabhas24423
44

Given:

➪The cost of cricket teams buys 7 bats and 6 balls for 3800 later she buys 3 bats and 5 balls for₹1750.

To find

➪Cost of each ball and bat

solution

➪let the cost of each bat be=₹ x

➪let the cost of each ball be = ₹ y

According to the Question

➪7x+6y=3800

6y= 3800-7x/6. _________ 1

➪3x+5y=175

putting the value y

3x+5 ((3800-7x))/6 = 1750

x= 500

y= (3800-7x)/6 = (3800-7(500))/6 = 50

y= 50

Hence the cost of each bat= Rs 500 and the each cost of balls = Rs 50✔︎✔︎✔︎✔︎✔︎✔︎✔︎

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