Question

The coach of a cricket team buys 7 bats and 6 balls for Rs.3800. Later, she buys 3 bats and 5 balls for Rs.1750. Find the cost of each bat and each ball.​

Answer 1

Let the cost of a bat be x and the cost of a ball be y.

According to the question,

7x + 6y = 3800 ………………. (i)

3x + 5y = 1750 ………………. (ii)

From (i), we get;

y = (3800 – 7x)/6 …………………… (iii)

Substituting (iii) in (ii). we get,

3x + 5[(3800 – 7x)/6] = 1750

⇒3x + (9500/3) – (35x/6) = 1750

3x – (35x/6) = 1750 – (9500/3)

(18x – 35x)/6 = (5250 – 9500)/3

⇒-17x/6 = -4250/3

⇒-17x = -8500

x = 500

Putting the value of x in (iii), we get;

y = (3800 – 7 × 500)/6 = 300/6 = 50

Hence, the cost of a bat is Rs 500 and cost of a ball is Rs 50.

Answer 2

Step-by-step explanation:

Let the cost of each bat be Rs. x and cost of each ball be Rs. y

Now as per the question

First he buys 7 bat and 6 balls for Rs. 3800

7x+6y=3800...(1)

Later he buys 3 bats and 5 balls for Rs. 1750

3x+5y=1750...(2)

Now using substitution method from eq2

5y=1750−3x

⇒y=

5

1750−3x

Now putting value of y in eq1

⇒7x+

5

6(1750−3x)

=3800

⇒35x+10500−18x=19000

⇒17x=8500

⇒x=500

Now putting value of x in eq2

⇒3×500+5y=1750

⇒1500+5y=1750

⇒5y=1750−1500

⇒5y=250

⇒y=50

Hence each bat cost = Rs. 500 and each ball cost = Rs. 50