Question

The coach of a cricket team buys 7 bats and 6 balls for Rs.3800. Later, she buys 3 bats and 5 balls for Rs.1750. Find the cost of each bat and each ball.​

Answer 1

Let the cost of a bat be x and the cost of a ball be y.

According to the question,

7x + 6y = 3800 ………………. (i)

3x + 5y = 1750 ………………. (ii)

From (i), we get;

y = (3800 – 7x)/6 …………………… (iii)

Substituting (iii) in (ii). we get,

3x + 5[(3800 – 7x)/6] = 1750

⇒3x + (9500/3) – (35x/6) = 1750

3x – (35x/6) = 1750 – (9500/3)

(18x – 35x)/6 = (5250 – 9500)/3

⇒-17x/6 = -4250/3

⇒-17x = -8500

x = 500

Putting the value of x in (iii), we get;

y = (3800 – 7 × 500)/6 = 300/6 = 50

Hence, the cost of a bat is Rs 500 and cost of a ball is Rs 50.

Answer 2

Answer:

Let us take the cost of each bat be Rs 'x' and cost of each ball be Rs 'y'

Now according to the question

First he buys 7 bat and 6 balls for Rs. 3800

7x+6y=3800 (equation 1)

Later he buys 3 bats and 5 balls for Rs. 1750

3x+5y=1750 (equation2)

Now using substitution method from equation 2

5y=1750−3x

=>y= 1750-3x

5

Now let us put the value of y in equation 1

=>7x+ 6(1750−3x) = 3800

5

=>35x+10500−18x=19000

=>17x=8500

=>x=500

Now putting value of x in equation2

=>3×500+5y=1750

=>1500+5y=1750

=>5y=1750−1500

=>5y=250

=>y=50

Hence, cost of each bat= Rs 500 and,

cost of each ball= Rs 50

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