The coach of a cricket team buys 7 bats and 6 balls for Rs. 3800. Later, she buys 3 bats and 5 balls for Rs. 1750.
Represent them algebraically.
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AnswerLet the cost of one Bat be x
AnswerLet the cost of one Bat be xand the cost of one ball be y
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get21x+18y=11400 (iii)
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get21x+18y=11400 (iii)21x+35y=12250 (iv)
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get21x+18y=11400 (iii)21x+35y=12250 (iv)subtracting (iv) from (iii) we get
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get21x+18y=11400 (iii)21x+35y=12250 (iv)subtracting (iv) from (iii) we get −17y=−850
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get21x+18y=11400 (iii)21x+35y=12250 (iv)subtracting (iv) from (iii) we get −17y=−850⇒y=50
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get21x+18y=11400 (iii)21x+35y=12250 (iv)subtracting (iv) from (iii) we get −17y=−850⇒y=50putting y=50 in (i)
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get21x+18y=11400 (iii)21x+35y=12250 (iv)subtracting (iv) from (iii) we get −17y=−850⇒y=50putting y=50 in (i)7x+6y=3800
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get21x+18y=11400 (iii)21x+35y=12250 (iv)subtracting (iv) from (iii) we get −17y=−850⇒y=50putting y=50 in (i)7x+6y=3800⇒7x+6×50=3800
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get21x+18y=11400 (iii)21x+35y=12250 (iv)subtracting (iv) from (iii) we get −17y=−850⇒y=50putting y=50 in (i)7x+6y=3800⇒7x+6×50=3800⇒7x=3800−300
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get21x+18y=11400 (iii)21x+35y=12250 (iv)subtracting (iv) from (iii) we get −17y=−850⇒y=50putting y=50 in (i)7x+6y=3800⇒7x+6×50=3800⇒7x=3800−300⇒x=500
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get21x+18y=11400 (iii)21x+35y=12250 (iv)subtracting (iv) from (iii) we get −17y=−850⇒y=50putting y=50 in (i)7x+6y=3800⇒7x+6×50=3800⇒7x=3800−300⇒x=500Therefore the cost of each bat is Rs 500
AnswerLet the cost of one Bat be xand the cost of one ball be yThen According to Question7x+6y=3800 ---(i)3x+5y=1750 ---(ii)multiplying (i) by 3 and (ii) by 7 we get21x+18y=11400 (iii)21x+35y=12250 (iv)subtracting (iv) from (iii) we get −17y=−850⇒y=50putting y=50 in (i)7x+6y=3800⇒7x+6×50=3800⇒7x=3800−300⇒x=500Therefore the cost of each bat is Rs 500and the cost of each ball is Rs 50
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