the coach of a cricket team buys 7bats and 6balls for rs.3800.later she buys 3bats and 5balls for rs. 1750 . find cost of each bat and ball by substitution methods
Answers
Answered by
1
the cost of bat is 500.
the cost of ball is 50
the cost of ball is 50
ayushiagrawal06:
that i also know bt i want solution of this by substitution method
Answered by
5
X=bats
Y=balls
7x + 6y= 3800 = eq1
3x + 5y = 1750 = eq2
( 7x + 6y = 3800) ×3
( 3x + 5y = 1750 ) × 7
21x + 18y = 11400
21x + 35y = 12250
+ - singn will change
-17y = - 850
Y = 50
By eq 1
7x + 6(50) =3800
7x + 300 = 3800
7x = 3800 - 300
7x = 3500
X= 3500 / 7
X = 500
Each bat's price = 500
Each ball's price = 50
Y=balls
7x + 6y= 3800 = eq1
3x + 5y = 1750 = eq2
( 7x + 6y = 3800) ×3
( 3x + 5y = 1750 ) × 7
21x + 18y = 11400
21x + 35y = 12250
+ - singn will change
-17y = - 850
Y = 50
By eq 1
7x + 6(50) =3800
7x + 300 = 3800
7x = 3800 - 300
7x = 3500
X= 3500 / 7
X = 500
Each bat's price = 500
Each ball's price = 50
How can you solve by substitution methods
Similar questions