Question

*The coach of cricket team buy 3 bats and 6 balls for Rs. 3900. What will be the algebraical equation of this situation .*

1️⃣ 3x - 3y = 1300
2️⃣ 3x + 2y = 3900
3️⃣ 3x - 6y = 3900
4️⃣ x + 3y = 1300​

Answer 1

Step-by-step explanation:

Answer

let rate of bat = xRs.

and rate of ball = yRs.

3x+6y=3900.(i)

and x+3y=1300.(ii)

or x=(1300−3y)

now equation (i) can be written as

3(1300−3y)+6y=3900

3900−9y+6y=3900

∴y=0

Ans:- x=1300

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Answer 2

Answer:

option 4 x + 3y = 1300

Step-by-step explanation:

let the cost of one bat be x

=> cost of three bats = 3x

let the cost of one ball be y

=> cost of 6 balls = 6y

ATQ

3x + 6y = 3900

= x + 3y = 1300