Question

the coach of cricket team buys 3 bats and 6 balls for rupess 3900. Later,she buyanother bat and 3 more balls of the kind for rupess 1300. Respresent this situation algebraically and graphically​

Answer 1

cost of bat= x

cost of ball =y

3x+6y=3900

x+2y=1300

again from equation (i)

3x+6y=3900

x=3900-6y/3

x=. 1300. 1100. 300

y=. 0. 100. 500

again from equation (ii)

x+2y=1300

x=1300-2y

x=. 1300. 900. 300

y=. 0. 200. 500

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Answer 2

Answer:

Step-by-step explanation:

let the no. of bats be x and balls be y

3x+6y= 3900 .......(1)

x+3y =1300........(2)

from eq 1

3x+6y=3900

x=3900-3y/3

put the value of x in eq (2)

3900-3y+3y/3=1300

3900-3y+3y=1300*3

3900=3900