The COD value of a water sample is 40ppm .Calculate the amount of acidified K2Cr 2O7 required to oxidise matter present in 500ml of that water sample ..
Answers
Answered by
0
Answer: COD value is 40 ppm. It means 106g of water sample require 40g of oxygen to oxidise the organic matter in it.
500 water →40×500106=2×10−2g of O2
500 mL water sample requires 2×10−2g of O2 to oxidise the organic matter present in it.
2×10−2g of O2≡49×2×10−28g of K2Cr2O7
Amount of K2Cr2O7 required to oxidise the organic matter present in the water sample is 0.1225g.
Explanation: please mark me as brainliest
Similar questions