Question

the coefficient of friction between an object of mass 10 kg and the floor is 0.1 calculate the minimum force required to move it

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Answer 1

Answer:

Explanation:

Coefficient of Friction (μ) = 0.1

Mass of object (m) = 10 kg

Acceleration due to gravity (g) = 9.8 $\frac{m}{s^{2}}$

Minimum Force required to move it = Limiting Friction = Normal Reaction x μ

= Weight x μ = μmg = 0.1 x 10 x 9.8 = 9.8 N

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