Question

The coefficient of friction between block & the mass is 0.5. Find the minimum value of 'F' needed to keep block at rest?[g = 10 m/s2] :
m is 10 kg​

Answer 1

Answer:

From the FBD, it is clear that N=F.

For the block to remain at rest, mg=f

And since static friction is self-adjusting, mg≤f

max

f

max

=μN=μF

∴μF≥mg⇒F≥

μ

mg

∴F≥

0.5

10×10

⇒F≥200 N

→QED.