Question

The coefficient of friction between car C and the inclined plane is 0.8. The maximum acceleration of the car, so that it may move up the plane inclined at an angle without slipping will be (angle between the sleeping edge and sloping adage of the plane is 30*)

Answer 1

Acceleration of car is 11.7 m/s²

Explanation:

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Given that

coefficient of friction ,μ = 0.8

slope of inclined surface ,θ=30⁰  

The force due to weight of car = m g sinθ

Force due to friction = μ m g cosθ

The acceleration of car = a

If the car goes up

m g sinθ + μ m g cosθ = m a

The maximum acceleration of car ,when it goes up is given as follows

$a=g(sin\theta + \mu cos\theta)\\\\a=9.81(sin30^{\circ}+0.8cos 30^{\circ})\\\\a=11.70\ m/s^2$

Answer 2

Answer:

coefficient of friction ,μ = 0.8

slope of inclined surface ,θ=30⁰  

The force due to weight of car = m g sinθ

Force due to friction = μ m g cosθ

The acceleration of car = a

If the car goes up

m g sinθ + μ m g cosθ = m a