Question

The coefficient of friction between the tyres and road is 0.4.The minimum distance covered before attaining a speed of 8ms-1 starting from rest is nearly (g=10ms-2)​

Answer 1

Answer:

let us say that the static friction coefficient μ = 0.4.

let the mass of the vehicle be m.  acceleration due to gravity = g

Force on the vehicle = F > μ m g  = 4 m for the vehicle to start.

Let us ignore the rolling friction, as it is very small.

Then acceleration a = F/ m = 4 m/s²

We know  v² = 2 a s

=>    s = 8²/(2 a) = 4 meters

If there is a rolling friction then the vehicle takes longer distances to attain that speed of 8 m/s

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