Question

The coefficient of friction between two surfaces isu = 0.8. The tension in the string (a) ON(0) 4N(b) 6N(d) 8N​

Answer 1

Answer:

Maximum frictional force acting on the block f=μmg cos30

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f=0.8×1×9.8×0.866=6.8 N

Downward force =mg sin30=1×9.8×0.5=4.9 N

Since downward force is less than maximum frictional force, thus the tension in the string is zero.

Explanation:

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