Question

The coefficient of friction is 0.75 if sin 37 degrees equal to 0.6 the angle of friction

Answer 1

Answer:

The Angle of friction is 37°

Explanation:  

Given;

sin37=0.6 or $(\frac{3}{5})$

$cos37'=\sqrt{1-\frac{3}{5}^2}\\ =\sqrt{1-(\frac{3}{5})^2}\\ =\sqrt{1-(\frac{9}{25})$

$=\sqrt{\frac{16}{25}}\\ cos37=\frac{4}{5}$

$tan37=\frac{3}{4}\\ =0.75$

Angle of Friction (t) = tan(co-efficient of friction)

$t=tan^{-1}(\frac{3}{4})\\t=37 degree$

Hope u find it helpful :)

Answer 2

Answer:

37 degrees

Explanation:

We are given that coefficient of friction is 0.75

$sin37^{\circ}=0.6=\frac{6}{10}=\frac{3}{5}$

$cos37^{\circ}=\sqrt{1-(\frac{3}{5})^2}$

$cos37^{\circ]=\sqrt{25-9}{25}=\frac{4}{5}$

We know that $tan\theta=\mu$

$tan37^{\circ}=\frac{sin37}{cos37}=\frac{\frac{3}{5}}{\frac{4}{5}}=\frac{3}{4}$

$tan 37=0.75$

Hence, the angle of friction is 37 degrees.