Question

The coefficient of linear expansion of gold is 14x 10^-6/°c.Find the coefficient of linear expansion fahrenheit scale

Answer 1

14×10^-6°c=57.2°F is your answer

Answer 2

The coefficient of linear expansion fahrenheit scale is $(4732 \times 10^{-7})^{\circ}F$

Step-by-step explanation:

Given :The coefficient of linear expansion of gold is $(14 \times 10^{-6})^{\circ}C$

To Find :Find the coefficient of linear expansion fahrenheit scale

Solution :

$1^{\circ}C=33.8^{\circ}F$

The coefficient of linear expansion of gold is $(14 \times 10^{-6})^{\circ}C$

$(14 \times 10^{-6})^{\circ}C=(33.8 \times 14 \times 10^{-6})^{\circ}F$

$(14 \times 10^{-6})^{\circ}C=(4732 \times 10^{-7})^{\circ}F$

Hence  the coefficient of linear expansion fahrenheit scale is $(4732 \times 10^{-7})^{\circ}F$

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