the coefficient of mutual induction of 2 coils is 4 mH. if a constant current flowing in one coil is 2A, then the induced emf in the second coil will be
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Answer:
The induced EMF in the second coil due to the current flowing in the first coil is 8×10^-3 V
Explanation:
Given
Coefficient of mutual inductance between two coils, which is equal to=4mH
Current flowing through one coil= 2A
We need to find the induced EMF in the second coil due to the current flowing in the second coil.
Induced EMF E= Coefficient of mutual inductance(M) ×current (I)
= 4××10^-3 ×2
=8×10^-3 V
The induced EMF in the second coil due to the current flowing in the first coil is 8×10^-3 V
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