The coefficient of performance of a carnot refrigerator is 5/3. If the refrigerator operating at a intake temperature -23°C then what will be the exhaust temperature
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The exhaust temperature would be 127°C.
Intake temperature is the lower temperature and exhaust temperature is the higher temperature.
Given, Intake temperature(T) = -23°C = (273-23) K =250 K [1K = 273°C]
Let exhaust temperature be T'
We know, coefficient of performance β = T/(T' - T)
Putting β as 5/3 and T as 250K, we get:
5/3 = 250/(T' - 250)
⇒ 5 × (T' - 250) = 3 × 250
⇒ (T' - 250) = 150
⇒ T' = (250 + 150) K = 400K = (400 - 273)°C = 127°C
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