Question

the coefficient of performance of a room air conditioner is 3.if the rate of doing work is 2kW,find the heat current​

Answer 1

The heat is current is 4 kJ/s

Explanation:

Given:

COP of a room conditioner is 3

Rate of doing work is 2kW = 2kJ/s

To find out:

The heat current

Solution:

We know that

$(COP)_R=\frac{Q_L}{W}$

Here,

$(COP)_R=3$

$W=2$ kW

$\therefore 2=\frac{Q_L}{2}$

$\implies Q_L=2\times 2=4$ kJ/s

Hope this answer is helpful.

Know More:

Q: A refrigerator whose coefficient of performance is 5 extracts heat from the cooling compartment at the rate of 250 j/cycle. How much electric energy is spent per cycle? How much heat per cycle is discharged to the room?

Click Here: https://brainly.in/question/8338212

Answer 2

Answer:

6kW

Explanation:

K=3

p=2kW

• Heat (H)=KP=3×2=6kW