Question

The coefficient of quartile deviation for a certain group of observation is 0.4. The sum of the two quartiles is 150. Then the values of two quartiles is​

Answer 1

Answer:

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Answer 2

Answer:

The values of the two quartiles are 105 and 45​

Step-by-step explanation:

• Quartile Deviation is equal to half of the Inter-Quartile Range.
• It is given by

               $Q_{d} =\frac{Q_{1}-Q_{2}}{2}$

• The coefficient of quartile deviation is given by

         $C=\frac{{Q_{1}-Q_{2}}}{{Q_{1}+Q_{2}}}$

Step 1 of 1:

• The coefficient of quartile deviation for a certain group is 0.4.
• The sum of the two quartiles is 150.
•       ${Q_{1}+Q_{2}}=150$
• By putting in the equation above,  it becomes

        $0.4=\frac{{Q_{1}-Q_{2}}}{{150}}}\\Q_{1}-Q_{2}=60$

• Now, the sum and difference of quantities are known.
• Adding both, it becomes

       $Q_{1}-Q_{2} +Q_{1}+Q_{2}=150+60\\2Q_{1}=210\\Q_{1}=105$

        $Q_{1}+Q_{2}=150\\105+Q_{2}=150\\Q_{2}=45$