Question

The coefficient of static friction. benveen block A of mass 2 kg and the table as shown in figure is 0.1
What should be the maximum mass of block B so that the two blocks do not move? The string and the pulley
are assumed to be smooth and massless. (g = 10 m/s).​

Answer 1

Answer:

ANSWER

The mass of the block A is 2kg, the coefficient of friction is 0.2.

As the blocks do not move therefore, the tension in the string must be equal to the force of friction on block A.

Applying Newton's second law for block A,

T=μ

s

m

A

g

=0.2×2×10

=4N

Applying Newton's second law for block B,

T=m

B

g

4=m

B

×10

m

B

=0.4kg

Thus, the maximum mass of the block B is 0.4k