Question

The coefficient of static friction of a body of mass 20kg tilted till it reaches an angle 30° is​

Answer 1

Given:

mass of body m = 20 kg

angle θ = 30°

To find:

The coefficient of static friction μ =?

Step-to-step-explanation:

• The frictional force at an inclined plane of the body is given by:

        F sinθ = μ F cosθ

        where

        F = frictional force

        θ = inclination angle

        μ = coefficient of static friction

• Remove F from both sides of the above equation

        sinθ = μ cosθ

• Rearranging the above equation we get:

        μ = tanθ

• Put θ = 30° in the above equation

       μ = tan 30°

      μ = 0.5773

• Hence the coefficient of static friction of a body of mass 20kg tilted till it reaches an angle of 30° is​ 0.5773.

Refer to the following attachment:

Answer 2

Answer:

Given:

mass of body m = 20 kg  

angle θ = 30°

To find:

The coefficient of static friction μ =?

The frictional force at an inclined plane of the body is given by:

       F sinθ = μ F cosθ

            where

F = frictional force

θ = inclination angle

 μ = coefficient of static friction

Remove F from both sides of the above equation

       sinθ = μ cosθ

Rearranging the above equation we get:

    μ = tanθ

Put θ = 30° in the above equation

      μ = tan 30°

μ = 0.5773

Hence the coefficient of static friction of a body of mass 20kg tilted till it reaches an angle of 30° is​ 0.5773.

Explanation:

Refer this attachment..

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