The coefficient of static friction us between block A of mass 2 kg and the table .What would be the maximum mass value of block B so that the two blocks do not move ?The string and the pulley are assumed to be smooth and massless ( g = 10 m/s²)
Answers
Answered by
4
Explanation:
The mass of the block A is 2kg, the coefficient of friction is 0.2.
As the blocks do not move therefore, the tension in the string must be equal to the force of friction on block A.
Applying Newton's second law for block A,
T=μ
s
m
A
g
=0.2×2×10
=4N
Applying Newton's second law for block B,
T=m
B
g
4=m
B
×10
m
B
=0.4kg
Thus, the maximum mass of the block B is 0.4kg.
Mark as brainlliest pls plspls
Similar questions