Question

The coefficient of t24 in the expansion of (1+t2)12(1+t12)(1+t24) is

Answer 1

Thank you for asking this question. Here is your answer:

First of all we will expand the equation: [1+t²]¹²

Into this:

coeff of t¹² = [t²] 6 = 12C⁶

coeff of t²⁴=12c₁₂

coeff of t²⁴ in given exp is 1*1+1*1+1*1+1*12c₁₂+1*12c₆

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