Math, asked by alifiyajariwala62, 1 month ago

the coefficient of w² in the expansion of (w-2)³ is​

Answers

Answered by suryanshsharma2613
0

Step-by-step explanation:

We know that the formula for (a+b)

3

is:

(a+b)

3

=a

3

+b

3

+3a

2

b+3ab

2

Now, let us substitute a=x and b=2 in the above formula as shown below:

(x+2)

3

=x

3

+2

3

+(3x

2

×2)+(3x×2

2

)

=x

3

+8+6x

2

+(3x×4)

=x

3

+8+6x

2

+12x

=x

3

+6x

2

+12x+8

From the above calculations, we observe that the coefficient of x

3

is 1, coefficient of x

2

is 6 and coefficient of x is 12.

Hence, the coefficient of x is 12.

Answered by dineshseethalam04
1

Answer:

(a-b) ³ = a³-b³-3a²b+3ab²

(w-2)³ = w³-2³-3*w²*2+3w*4

(w-2)³ = w³-8-6w²+12w

hence coefficient of x² is -6

Similar questions