Question

The coefficient of x^2 in the expansion(x+4)^3,is​

Answer 1

Answer:

(x-4)³

x³-3•x²•4+3•x•4²-4³

x³-12x²+48x-64

hence The coefficient of x² is -12

#666

Answer 2

Step-by-step explanation:

${x + 4}^{3}$

$= {x}^{3} + {4}^{3} + 3 \times x \times 4 \times x + 4$

$= {x}^{3} + 64 + 12x \times x + 4$

$= {x}^{3} + 68 + {12x}^{2}$

Therefore the coefficient of x^2 =

${x}^{3} + 68 + 12$