the coefficient of x^2 in (x^2+2)whole cube is
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0
Answer:
1
Step-by-step explanation:
i think so coz....since there is no visible number as its co-efficient it is safe to say 1...
mark me as brainliest....thats if u find it brainlier ..tnx
Answered by
0
Step-by-step explanation:
(x^2+2)^3
(a+b)^3=a^3+b^3+3ab(a+b)
= (x^2)^3+(2)^3+3x^2×2(x^2+2)
= x^6+8+6x^2(x^2+2)
=x^6+8+6x^4+12x^2
So the coefficient of x^2is 12
I think u Understand the answer.
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