Math, asked by lucky2304, 8 months ago

The coefficient of x^n in the expansion of 1/(2-x)(1-2x)(1-3x) is

Answers

Answered by SwaggerGabru
12

\huge\red{\underline{{\boxed{\textbf{QUESTION}}}}}

The coefficient of x^n in the expansion of 1/(2-x)(1-2x)(1-3x) is

\huge\red{\underline{{\boxed{\textbf{ANSWER}}}}}

1/(2-x)(1-2x)(1-3x)

We can see in this given expression that, we will never get the solution of

 {x}^{n}

Because through expression we do not get any coefficient hence,

The coefficient of the {x}^{n} is 0.

@HarshPratapSingh

Answered by nisha382
49

Answer:

{\huge{\blue{\underline{\bold{Hello\:Mate}}}}}

 \frac{1}{(2 - x)(1 - 2x)(1 - 3x)}

 =  \frac{1}{(2 {x}^{2} - 5x + 2)(1 - 3x) }

 =  \frac{1}{ - 6 {x}^{3} + 17 {x}^{2}  - 11x + 2 }

From the given Expression,We cant get the coefficient of x^n.

•°•coefficient of x^n is 0

Thanks ❤️❤️

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