The coefficient of x11 in the expansion of (1 + x)(1 +
x2)(1 + x) ... (1 + x12) is
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1
Answer:
hope it helps
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Step-by-step explanation:
(1+x+x2+x3)11=(1−x41−x)11
=(1−x4)11×(1−x)−11
=(1+11C1(−x)4+...)×(1+(−11)(−x)+(−11)(−12)(−x2)(1×2)+...
Coefficientx4=(−11)(−12)(−13)(−14)1×2×3×4−11C1
=1001−11
=990
Answered by
0
Answer:
990
Step-by-step explanation:
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