Question

The coefficient of x²

in (px² + 4x + r) ×(4x²–3qx –5) is.........​

Answer 1

Answer:

Step-by-step explanation:

(px² + 4x + r) ×(4x²–3qx –5)

4px^4-3pqx^3-5px^2+16x^3-12qx^2-20x+4rx^2-3qrx-5r

so the terms which contains x^2 are

-5px^2,-12qx^2,+4rx^2

so –5p – 12q + 4r are the coefficient