Question

The coefficient of x² in the
expansion of (x+3)3 is​

Answer 1

Answer:

0

Step-by-step explanation:

(x+3)3=3x+9

there is no x² so the coefficient of x² is 0

Answer 2

Answer:

the answer is 9

Step-by-step explanation:

since,

(a+b)^3=a^3+b^3+3ab(a+b)

(x+3)^3=x^3+3^3+3*x*3(x+3)

=x^3+27+9x(x+3)

=x^3+27+9x^2+27x

=x^3+9x^2+27x+27

therefore the coefficient of x^2 in 9x^2 is 9

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