Question

the coefficient of x2 in the polynomial 3+5xm x 4 - 3 x 2.
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Answer 1

Answer:

5 is the correct answer Pls mark as brainliest

Answer 2

$∴WorkDonebyforceapplied=200J</p><p></p><p>\green{\tt{\therefore{Work\:Done\:by\:frictional\:force=-50\:J}}}∴WorkDonebyfrictionalforce=−50J</p><p></p><p>\green{\tt{\therefore{Work\:Done\:by\:weight\:of\:box=0\:J}}}∴WorkDonebyweightofbox=0J</p><p></p><p>\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}} </p><p>Step−by−stepexplanation:</p><p> </p><p> </p><p> </p><p> </p><p></p><p>\green{\underline{\bold{Given :}}} </p><p>Given:</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt: \implies Mass \: of \: box (m)= 10 \: kg\\\end{gathered} </p><p>:⟹Massofbox(m)=10kg</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt: \implies Applied \: force(F) = 100 \:N \\\end{gathered} </p><p>:⟹Appliedforce(F)=100N</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt: \implies Friction \: force(fr) = 25 \: N\\\end{gathered} </p><p>:⟹Frictionforce(fr)=25N</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt: \implies Displacement(s) = 2 \: m \\\end{gathered} </p><p>:⟹Displacement(s)=2m</p><p> </p><p> </p><p></p><p>\red{\underline{\bold{To \: Find :}}} </p><p>ToFind:</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt: \implies Work \: Done \: by \: applied \: force(w_{F} ) = ? \\\end{gathered} </p><p>:⟹WorkDonebyappliedforce(w </p><p>F</p><p> </p><p> )=?</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt: \implies Work \: Done \: by \: frictional \: force(w_{fr} ) =? \\\end{gathered} </p><p>:⟹WorkDonebyfrictionalforce(w </p><p>fr</p><p> </p><p> )=?</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt: \implies Work \: Done \: by \: weight \:of \: box(w_{m} ) = ? \\\end{gathered} </p><p>:⟹WorkDonebyweightofbox(w </p><p>m</p><p> </p><p> )=?</p><p> </p><p> </p><p></p><p>• According to given question :</p><p>\bold{As \: we \: know \: that}Asweknowthat</p><p></p><p>\begin{gathered}\tt: \implies Work \: done = Force \: applied \times Displacement \\\end{gathered} </p><p>:⟹Workdone=Forceapplied×Displacement</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt: \implies w_{F} = 100 \times 2 \\\end{gathered} </p><p>:⟹w </p><p>F</p><p> </p><p> =100×2</p><p> </p><p> </p><p></p><p>\begin{gathered}\green{\tt: \implies w_{F} = 200 \: joule} \\\end{gathered} </p><p>:⟹w </p><p>F</p><p> </p><p> =200joule</p><p> </p><p> </p><p></p><p>\bold{Again: }Again:</p><p></p><p>\begin{gathered}\tt: \implies w_{fr} =fs\: cos \: \theta \\\end{gathered} </p><p>:⟹w </p><p>fr</p><p> </p><p> =fscosθ</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt: \implies w_{fr} = 25 \times 2 \times cos \: 180 \degree \\\end{gathered} </p><p>:⟹w </p><p>fr</p><p> </p><p> =25×2×cos180°</p><p> </p><p> </p><p></p><p>\begin{gathered}\green{\tt: \implies w_{fr} = - 50 \: joule} \\\end{gathered} </p><p>:⟹w </p><p>fr</p><p> </p><p> =−50joule</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt \circ \: Weight \: of \: box = mg = 100 \: N \\\end{gathered} </p><p>∘Weightofbox=mg=100N</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt \circ \: Angle \: between \: force \: and \: displacement = 90 \degree\\\end{gathered} </p><p>∘Anglebetweenforceanddisplacement=90°</p><p> </p><p> </p><p></p><p>\bold{Similarly : }Similarly:</p><p></p><p>\begin{gathered}\tt: \implies w_{m} = fs \: cos \: \theta \\\end{gathered} </p><p>:⟹w </p><p>m</p><p> </p><p> =fscosθ</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt: \implies w_{m} = 100 \times 2 \times cos \: 90 \degree \\\end{gathered} </p><p>:⟹w </p><p>m</p><p> </p><p> =100×2×cos90°</p><p> </p><p> </p><p></p><p>\begin{gathered}\tt: \implies w_{m} = 100 \times 2 \times 0 \\\end{gathered} </p><p>:⟹w </p><p>m</p><p> </p><p> =100×2×0</p><p> </p><p> </p><p></p><p>\green{ \tt: \implies w_{m} = 0 \: joule}:⟹w </p><p>m</p><p> </p><p> =0joule$