Question

The coefficient of x³ in 16x² - 26x + 10 is
options are
1. 2
2. 3
3. -1
4. 0
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Anwesha dii - what is incorrect​

Answer 1

Answer:

the coefficient of x3 in 16x2 - 26x +10 is o

Step-by-step explanation:

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Answer 2

Answer:

p(x) = x³ – 4x² + 5x - 2; 2, 1, 1

p(2) = (2)³ – 4 x (2)² + 5 x 2 - 2

= 8 - 16 + 10 - 2

= 18 - 18 = 0

p(1) = (1)³ – 4 x (1)² + 5 x 1 - 2

= 1 - 4 + 5 - 2

= 6 - 6 = 0

So, 2, 1, 1 are the zeroes of the cubic polynomial p(x) = x³ – 4x² + 5x - 2.

In general, cubic polynomial is ax³ + bx² + cx + d

p(x) = x³ – 4x² + 5x - 2

By compairing, a = 1, b = -4, c = 5, d = -2.

Relationship between the zeroes and the coefficients :

Given that α = 2, β = 1, γ = 1

α + β + γ = 2 + 1 + 1 = 4

-b/a = -(-4)/1 = 4

αβ + βγ + γα = 2 x 1 + 1 x 1 + 1 x 2

= 2 + 1 + 2 = 5

c/a = 5/1 = 5

αβγ = 2 x 1 x 1 = 2

-d/a = -(-2)/1 = 2

Hence option 1 is right..

Step-by-step explanation:

Hope it helps.