The coefficient of x³ in 16x² - 26x + 10 is
options are
1. 2
2. 3
3. -1
4. 0
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Anwesha dii - what is incorrect
Answers
Answer:
the coefficient of x3 in 16x2 - 26x +10 is o
Step-by-step explanation:
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Answer:
p(x) = x³ – 4x² + 5x - 2; 2, 1, 1
p(2) = (2)³ – 4 x (2)² + 5 x 2 - 2
= 8 - 16 + 10 - 2
= 18 - 18 = 0
p(1) = (1)³ – 4 x (1)² + 5 x 1 - 2
= 1 - 4 + 5 - 2
= 6 - 6 = 0
So, 2, 1, 1 are the zeroes of the cubic polynomial p(x) = x³ – 4x² + 5x - 2.
In general, cubic polynomial is ax³ + bx² + cx + d
p(x) = x³ – 4x² + 5x - 2
By compairing, a = 1, b = -4, c = 5, d = -2.
Relationship between the zeroes and the coefficients :
Given that α = 2, β = 1, γ = 1
α + β + γ = 2 + 1 + 1 = 4
-b/a = -(-4)/1 = 4
αβ + βγ + γα = 2 x 1 + 1 x 1 + 1 x 2
= 2 + 1 + 2 = 5
c/a = 5/1 = 5
αβγ = 2 x 1 x 1 = 2
-d/a = -(-2)/1 = 2
Hence option 1 is right..
Step-by-step explanation:
Hope it helps.