The coefficients of two metallic conductors A and B of equal length are 1.6x10-82m and 3.2x10-82 - m respectively! The two conductors are connected separately at the same voltage. What is the ratio of their cross-sections, the flow rate is the same in each of them
Answers
Answer:
Resistance R of a wire of length l and cross sectional area A (thickness) is given by ,
R=ρl/A
where ρ= specific resistance of wire
for copper wire R=ρ
c
l/A
c
,
for manganin wire R=ρ
m
l/A
m
or ρ
c
/A
c
=ρ
m
/A
m
or A
c
/A
m
=ρ
c
/ρ
m
we know ρ
m
>ρ
c
(as manganin is an alloy)
therefore A
c
<A
m
Hence manganin wire is thicker.
Video Explanation
Answer:
Resistance R of a wire of length l and cross sectional area A (thickness) is given by ,
R=ρl/A
where ρ= specific resistance of wire
for copper wire R=ρcl/Ac ,
for manganin wire R=ρml/Am
or ρc/Ac=ρm/Am
or Ac/Am=ρc/ρm
we know ρm>ρc (as manganin is an alloy)
therefore Ac<Am
Hence manganin wire is thicker.
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Step-by-step explanation:
Resistance R of a wire of length l and cross sectional area A (thickness) is given by ,
R=ρl/A
where ρ= specific resistance of wire
for copper wire R=ρcl/Ac ,
for manganin wire R=ρml/Am
or ρc/Ac=ρm/Am
or Ac/Am=ρc/ρm
we know ρm>ρc (as manganin is an alloy)
therefore Ac<Am
Hence manganin wire is thicker.
Please Mark It as Brainliest