Math, asked by shibdutta640, 1 month ago

The coefficients of two metallic conductors A and B of equal length are 1.6x10-82m and 3.2x10-82 - m respectively! The two conductors are connected separately at the same voltage. What is the ratio of their cross-sections, the flow rate is the same in each of them​

Answers

Answered by llchummill
0

Answer:

Resistance R of a wire of length l and cross sectional area A (thickness) is given by ,

R=ρl/A

where ρ= specific resistance of wire

for copper wire R=ρ

c

l/A

c

,

for manganin wire R=ρ

m

l/A

m

or ρ

c

/A

c

m

/A

m

or A

c

/A

m

c

m

we know ρ

m

c

(as manganin is an alloy)

therefore A

c

<A

m

Hence manganin wire is thicker.

Video Explanation

Answered by NamanSheoran
0

Answer:

Resistance R of a wire of length l and cross sectional area A (thickness) is given by ,

         R=ρl/A

where ρ= specific resistance of wire

for copper wire      R=ρc​l/Ac​ ,

for manganin wire  R=ρm​l/Am​

or                          ρc​/Ac​=ρm​/Am​

or                          Ac​/Am​=ρc​/ρm​

we know  ρm​>ρc​  (as manganin is an alloy)

therefore               Ac​<Am​

Hence manganin wire is thicker.

Please Mark It as Brainliest

Step-by-step explanation:

Resistance R of a wire of length l and cross sectional area A (thickness) is given by ,

         R=ρl/A

where ρ= specific resistance of wire

for copper wire      R=ρc​l/Ac​ ,

for manganin wire  R=ρm​l/Am​

or                          ρc​/Ac​=ρm​/Am​

or                          Ac​/Am​=ρc​/ρm​

we know  ρm​>ρc​  (as manganin is an alloy)

therefore               Ac​<Am​

Hence manganin wire is thicker.

Please Mark It as Brainliest

Similar questions