Chemistry, asked by Missnotanki79, 16 days ago

The coefficients of variations for the two distributions are 60 and 70 and its standard deviations are 21 and 16 respectively. Determine its arithmetic mean.​

Answers

Answered by PRINCE100001
44

Explanation:

Given :-

The coffiecients of variations for the two distribution are 60 and 70 .

The standard deviation for 60 and 70 are 21 and 16 respectively.

Solution :-

Here, we have to calculate its arithmetic mean

For first distribution ,

We have ,

Coffiecients of variations = 60

Standard deviation = 21

Let the mean be x

As we know that,

Coffiecients of variations

= Standard deviation / mean * 100

Put the required values,

60 = 21 / x * 100

60x = 2100

x = 2100/60

x = 210/6

x = 35

Thus, The mean for first distribution is 35

Now,

For second distribution ,

We have,

Coffiecients of variations = 70

Standard deviations = 16

Let the mean be y

As we know that,

Coffiecients of variations

= Standard deviation / mean * 100

Put the required values,

70 = 16/y * 100

70y = 1600

y = 1600/70

y = 160/7

y = 22.85

Thus, The mean for second distribution is 22.85

Hence, The arithmetic mean is 35 and 22.85 ..

Answered by shrutikshajadhav
1

Answer:

For first distribution:

Coefficient of variation (cv)=60

We know that

cv=Meanstandard deviation×100

60=Mean21×100

Mean=6021×100

=35

For sound distribution

Coefficient of variation (cv)=70

standard deviation =16

We know that

cv=Meanstand and deviation×100

70=Mean16×100

Mean =7016×100=22.85

Explanation:

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