Question

the coefficients of x in the expansion of (x3)²
with ealxplantaion​

Answer 1

Answer:

ANSWER

(2−x)

6

=64−192x+240x

2

−160x

3

+20x

4

−12x

5

+x

6

Coeff of x

2

is 240

Coeff of x

3

is −160

Step-by-step explanation:

hope its help you my dear friend

Answer 2

Answer:

(X×3)

2

=9x

2

thereorecoefficientofxis0