Question

The coifficent of self inductance of two coil l1 and l2 to induce and emf 25v in the coil change of current 1A has to be produce in 5 sec and 50ms resp the ratio of l1 and l2 wii be

Answer 1

Answer:

hey dud there is mistake in your question

50ms?

Answer 2

Given: emf = 25V

           change in current = 1A

            t₁ = 5 sec and t₂ = 50 ms or 0.05 sec

To Find: ratio of L₁ and L₂

Formula used: emf = L($-\frac{dI}{dt}$)

            25 = L₁( $-\frac{1}{5}$)     (equation 1)

            25 = L₂($-\frac{1}{0.05}$)  (equation 2)

            solving equation 1 and 2 we get,

            $\frac{L1}{L2}$ = $\frac{100}{1}$

So, the ratio of self inductance of two coils L₁ and L₂ comes out to be $\frac{100}{1}$