Question

The coil having a resistance of 10 ohm and
an inductance of 0.2 H is connected to a
100-V, 50-Hz supply. Calculate (a) the
impedance of the coil (b) the reactance of
the coil (c) the current taken and (d) the
phase difference between the current and
the applied voltage.​

Answer 1

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Answer 2

Given:

resistance of coil = 10 ohm

Inductance = 0.2 H

Frequency = 50 Hz

Voltage supply = 100 V

To Find:

the impedance of the coil , the reactance of the coil, the current taken and the phase difference between the current and the applied voltage.

Explanation:

Using the formula for impedance

Z = √R² + X²

  = √(10)² + ( 2π×50×0.2)²

  = 63.622Ω

Reactance of coil

X = 2πfL

   = 2π×50×0.2

  = 62.831Ω

Current I = V/Z

              = 100/33.622

               = 1.5717A

For Phase difference

Cos ∅ = R/Z

          = 10/63.622

          = 0.157

Answer = 62.831Ω , 1.5717A ,  0.157