Question

the coil of heater is cut into two equal halves and only one of them is used in the heater . what is the ratio of heat producedby half of the coil to the original coil?

Answer 1

Explanation:

We know that R=ρ

A

L

Hence, on cutting half R

′

=

2

R

And for same end potential difference as in house hold circuits-

H=

R

V

2

⟹H∝

R

1

⟹

H

H

′

=

R

′

R

=2

Answer 2

Answer:

When heater coil is cut into two equal coil then length get halved.

So following it resistance is also reduced to half.

H=V²/R.

By using this we can conclude that if resistance is halved then heat produced is doubled.

Hope! u felt helpful wih my answer