Question

the coil of moving coil galvanometer has 50 turns and its resistance 10 if it is replaced by a coil that has 100 turns and resistance 50 ohm find the voltage sensitivity and current sensitivity​

Answer 1

Explanation:

the coil of moving coil galvanometer has 50 turns and its resistance 10 if it is replaced by a coil that has 100 turns and resistance 50 ohm find the voltage sensitivity and current sensitivity

Answer 2

Answer:

Voltage sensitivity of coil A = 5

Voltage sensitivity of coil  B = 2

Explanation:

Number of turns in coil A = 50

Resistance of coil A = 10Ω

Number of turns in coil B = 100

Resistance of coil B = 50 Ω

Voltage sensitivity of moving coil galvanometer = $\frac{No. of turn}{Resistance}$

For coil A = $\frac{N A}{R A}$ = 5

For coil B = $\frac{N B}{R B}$ = 2

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