Question

. The coins of 5, 2 and 1 denomination in a bag have a ratio 1:3:8. In the aggregate the
coins are worth 380. Find number of each cash denomination.​

Answer 1

Answer:

Let the ratio be x:3x:8x.

According to Question,

5(x) + 2(3x) + 1(8x) = 380

=> 5x + 6x + 8x = 380

=> 19x = 380

=> x = 380/19

=> x = 20

Number of Rs.5 coins = 20

Number of Rs.2 coins = 60

Number of Rs.1 coins = 160

Answer 2

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5×1+ 2×3 + 1×8 = 19

380 / 19 = 20

₹5 - 20 × 1 = 20

₹2 - 20 × 3 = 60

₹1 - 20 × 8 = 160.

So, the Dominations are :-

₹5 = 20

₹2 = 60

₹1 = 160