Physics, asked by mahasamymahasamy, 2 months ago

The combination of three resistor ,R1=2ohm,R2=12ohm and R3=6ohm are connected in series , 12V potential difference across the resistors.
1.Total current flowing in circuit.
2.Total Resistance of the circuit​

Answers

Answered by sirapanasettynavyasr
1

Explanation:

R1=3ohm R2=4ohm,R3=6ohm

As the resistors are connected in parallel

1/Rtotal=1/3+1/4+1/6

1/Rtotal=(4+3+2)/12

1/Rtotal=9/12

Rtotal=12/9

Rtotal=4/3 ohm

Total current=Voltage /Rtotal

Itotal=2/(4/3)

Itotal=6/4

Itotal=3/2 Ampere

For resistance in the parallel ,voltage across each resistor is same and total current is sum of current through each resistor.

Current through R1=V/R1=2/3 Ampere

Current through R1=V/R2=2/4=1/2Ampere

Current through R1=V/R3=2/6=1/3Ampere

Total current is 3/2 Ampere

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