The combined age of husband and wife are three times the combined ages of their children. Three years ago the ratio of their ages was 4 : 1, while 5 years after the ratio will be 20:9. How many children have they?
Answers
Given : The combined age of husband and wife are three times the combined ages of their children. Three years ago the ratio of their ages was 4 : 1, while 5 years after the ratio will be 20:9.
To Find : How many children have they?
Solution:
Let say number of children = n
Combined Age of n Children = A
combined age of husband and wife = 3A
Three years ago combined age of husband and wife = 3A - 2 * 3 = 3A - 6
Three years ago combined age Combined Age of n Children = A - n * 3 = A - 3n
Three years ago the ratio of their ages was 4 : 1
=> 3A - 6 = 4(A - 3n)
=> 3A - 6 = 4A - 12n
=> A = 12n - 6
5 years After combined age of husband and wife = 3A+ 2 * 5 = 3A+10
5 years After combined age Combined Age of n Children = A+ n * 5 = A +5n
5 years after the ratio will be 20:9
=> 9(3A + 10) = 20(A + 5n)
=> 27A +90 = 20A +100n
=> 7A = 100n-90
12n - 6
=> 7 (12n - 6) = 100n-90
=> 84n - 42 = 100n-90
=> 16n =48
=> n = 3
Number of children = 3
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The combined age of husband and wife are three times the combined ages of their children. Three years ago the ratio of their ages was 4 : 1, while 5 years after the ratio will be 20:9. How many children have they?
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➤Let take number of children = n
➤Combined Age of n Children = x
➤combined age of husband and wife = 3x
➤Three years ago combined age of
➤husband and wife 3x -2 3= 3x 6
Three years ago combined age
Combined Age of n Children = x - n *3
x=3n
Three years ago the ratio of their ages
was 4:1
=3x-6= 4(x - 3n)
=>3x- 6 = 4x -12n
=>x=12n-6
5 years After combined age of husband
and wife = 3x+ 2×5= 3x+10
5 years After combined age Combined
Age of n Children = x+n×5= x+5n
5 years after the ratio will be 20:9
9(3x +10)= 20(x+5n)
=>27x +90= 20x +100n
=7x =10On-90
12n- 6
=>7 (12n- 6) =100n-90
=>84n -42 =100n-90
=>16n =48
=>n = 33
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