Question

The combined ages of a father and his son are 36. In seven years' time the father will be fours times as old as his son. Find their current ages.

Answer 1

Answer:

The present age of father is 33 years and son is 3 years.

Step-by-step explanation:

Given :

The combined ages of a father and his son are 36. In seven years' time the father will be fours times as old as his son.

To find :

their current ages

Solution :

Let the present age of father be x and that of son be y.

x + y = 36

x = 36 - y ––(1)

After 7 years,

Father's age = x + 7

Son's age = y + 7

According to the question,

x + 7 = 4(y + 7)

x + 7 = 4y + 28

x - 4y = 28 - 7

x - 4y = 21

36 - y - 4y = 21

36 - 21 = 5y

5y = 15

y = 15/5

y = 3

The value of x :

x = 36 - y

x = 36 - 3

x = 33

Therefore, the present age of father is 33 years and son is 3 years.

Answer 2

QUESTION:-

The combined ages of a father and his son are 36. In seven years' time the father will be fours times as old as his son. Find their current ages.

EXPLANATION:-

Let the present age of son=x years

And that of father=y years

x+y=36--------eq-1  

AFTER 7 YEARS

Son=x+7

Father=y+7

4(x+7)=y+7

4x+28=y+7--------eq-2

From eq-1 and eq-2

x=36-y

Substitute x=36-y in eq-2

4(36-y)+28=y+7

-4y+172=y+7

So,

y=33

Put y=33 in eq-1

and x=3 years

So father=33 years and son=3 years

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