Question

The combined resistance of two identical resistors connected in series is 8 ohm their combined resistance in a parallel arrangement will be
A: 2 ohm
B: 4 ohm
C: 8 ohm
D: 12 ohm

Answer 1

Explanation:

resistance will be 2 ohm

Answer 2

$R_p=2\Omega$

Explanation:

Given:

Resultant of two identical resistors in series, $R_s=8\ \Omega$

so,

$R_s=R+R$

$8=2R$

$R=4\Omega$

NOW, when the two resistors are in series:

$\frac{1}{R_p} =\frac{1}{R} +\frac{1}{R}$

$\frac{1}{R_p} =\frac{2}{R}$

$R_p=2\Omega$

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TOPIC: resistance in parallel.

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