the combined resistance to two identical resistors, connected in series is 8 ohm . their combined resistance in a parallel arrangement will be
Answers
Answer:
I assume that by, “if combined resistance of two identical resistors is 8” you mean these two are in series… If that is the case then the value of each is 4. So two 4 Ohms resistor in parallel is 2 Ohms… You can do that one in your head. The formula is 1/x = 1/R1 + 1/R2. When resistance values are equal it really easy to do in you head as you will get 1/2 the value of one of them… to get down to 1 Ohm’s you would need 4, 8 Ohm resistor…
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Answer: 2 ohm
Explanation:
Given that two resistors are identical so they have equal resistance, and equivalent resistance is 8 ohm when connected in series.
So resistance of each resistor will be = 8/2 =4 ohm.
Now if we connect both 4 ohm resistor in parallel than equivalent resistance will be =(1/4)+(1/4)
= (4*4)/(4+4)
=16/8
=2 ohm.
So combined resistance in parallel connection is 2 ohm.